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excel vba bit mask
By 
Excel Hero
on May 27, 2020
Excel Hero
on May 27, 2020
'VBA function to create a bitmask in a Long Integer:
Function BitMask&(ParamArray a())
Dim i&, n&, m
For i = 0 To UBound(a)
If i > 31 Then Exit Function
m = a(i)
If m <> 0 Then
If Len(m) Then
BitMask = BitMask Or Abs(m) * 2 ^ i
End If
End If
Next
End Function
'-----------------------------------------------------------------------------
Dim mask&
mask = BitMask(1, 0, 0, 0, 1)
MsgBox mask '<--displays: 17 (00000000000000000000000000010001)
mask = BitMask(False, True, True)
MsgBox mask '<--displays: 6 (00000000000000000000000000000110)
'-----------------------------------------------------------------------------
'The above function is fast. But for the fastest possible native code,
'exponentiation (slow) can be optimized, by a lookup table. The following
'function uses the ShiftLeft() function, which is highly optimized. It is
'literally a hundred times faster:
Function BitMask&(ParamArray a())
Dim i&, n&, m
For i = 0 To UBound(a)
If i > 31 Then Exit Function
m = a(i)
If m <> 0 Then
If Len(m) Then
BitMask = BitMask Or ShiftLeft(Abs(m), i)
End If
End If
Next
End Function
Function ShiftLeft&(ByVal n&, Optional ByVal shifts& = 1)
Dim d&
Select Case shifts
Case 1: d = 2& * (n And 1073741823): If n And 1073741824 Then d = d Or &H80000000
Case 2: d = 4& * (n And 536870911): If n And 536870912 Then d = d Or &H80000000
Case 3: d = 8& * (n And 268435455): If n And 268435456 Then d = d Or &H80000000
Case 4: d = 16& * (n And 134217727): If n And 134217728 Then d = d Or &H80000000
Case 5: d = 32& * (n And 67108863): If n And 67108864 Then d = d Or &H80000000
Case 6: d = 64& * (n And 33554431): If n And 33554432 Then d = d Or &H80000000
Case 7: d = 128& * (n And 16777215): If n And 16777216 Then d = d Or &H80000000
Case 8: d = 256& * (n And 8388607): If n And 8388608 Then d = d Or &H80000000
Case 9: d = 512& * (n And 4194303): If n And 4194304 Then d = d Or &H80000000
Case 10: d = 1024& * (n And 2097151): If n And 2097152 Then d = d Or &H80000000
Case 11: d = 2048& * (n And 1048575): If n And 1048576 Then d = d Or &H80000000
Case 12: d = 4096& * (n And 524287): If n And 524288 Then d = d Or &H80000000
Case 13: d = 8192& * (n And 262143): If n And 262144 Then d = d Or &H80000000
Case 14: d = 16384& * (n And 131071): If n And 131072 Then d = d Or &H80000000
Case 15: d = 32768 * (n And 65535): If n And 65536 Then d = d Or &H80000000
Case 16: d = 65536 * (n And 32767&): If n And 32768 Then d = d Or &H80000000
Case 17: d = 131072 * (n And 16383&): If n And 16384& Then d = d Or &H80000000
Case 18: d = 262144 * (n And 8191&): If n And 8192& Then d = d Or &H80000000
Case 19: d = 524288 * (n And 4095&): If n And 4096& Then d = d Or &H80000000
Case 20: d = 1048576 * (n And 2047&): If n And 2048& Then d = d Or &H80000000
Case 21: d = 2097152 * (n And 1023&): If n And 1024& Then d = d Or &H80000000
Case 22: d = 4194304 * (n And 511&): If n And 512& Then d = d Or &H80000000
Case 23: d = 8388608 * (n And 255&): If n And 256& Then d = d Or &H80000000
Case 24: d = 16777216 * (n And 127&): If n And 128& Then d = d Or &H80000000
Case 25: d = 33554432 * (n And 63&): If n And 64& Then d = d Or &H80000000
Case 26: d = 67108864 * (n And 31&): If n And 32& Then d = d Or &H80000000
Case 27: d = 134217728 * (n And 15&): If n And 16& Then d = d Or &H80000000
Case 28: d = 268435456 * (n And 7&): If n And 8& Then d = d Or &H80000000
Case 29: d = 536870912 * (n And 3&): If n And 4& Then d = d Or &H80000000
Case 30: d = 1073741824 * (n And 1&): If n And 2& Then d = d Or &H80000000
Case 31: If n And &H1& Then d = &H80000000 Else d = &H0&
Case 0: d = n
End Select
ShiftLeft = d
End Function
Source: academy.excelhero.com
11
excel vba binary from byte value
By Excel Hero
on May 23, 2020
Excel Hero
on May 23, 2020
Public Function ByteToBits$(ByVal n&)
ByteToBits = "00000000"
If n And 1 Then MidB$(ByteToBits, 15) = "1"
If n And 2 Then MidB$(ByteToBits, 13) = "1"
If n And 4 Then MidB$(ByteToBits, 11) = "1"
If n And 8 Then MidB$(ByteToBits, 9) = "1"
If n And 16 Then MidB$(ByteToBits, 7) = "1"
If n And 32 Then MidB$(ByteToBits, 5) = "1"
If n And 64 Then MidB$(ByteToBits, 3) = "1"
If n And 128 Then MidB$(ByteToBits, 1) = "1"
End Function
'------------------------------------------------------------------------------
MsgBox ByteToBits(0) '<--displays: 00000000
MsgBox ByteToBits(170) '<--displays: 10101010
MsgBox ByteToBits(255) '<--displays: 11111111Source: academy.excelhero.com
9
excel vba long to bits
By Excel Hero
on May 27, 2020
Excel Hero
on May 27, 2020
Function LongToBits$(ByVal n&)
Dim i&
LongToBits = "00000000000000000000000000000000"
If n And &H80000000 Then
Mid$(LongToBits, 1, 1) = "1"
n = n And Not &H80000000
End If
For i = 32 To 2 Step -1
If n And 1 Then Mid$(LongToBits, i, 1) = "1"
n = n \ 2
Next
End Function
'------------------------------------------------------------------------------
MsgBox ByteToBits(0) '<--displays: 00000000000000000000000000000000
MsgBox LongToBits(293781237) '<--displays: 00010001100000101011111011110101
MsgBox ByteToBits(-1) '<--displays: 11111111111111111111111111111111
Source: academy.excelhero.com
7
vba is bit set in integer
By Excel Hero
on Feb 05, 2021
Excel Hero
on Feb 05, 2021
'Extremely fast VBA function to test if a specified bit is set
'within a 16-bit Integer.
'Bits are numbered from 0 to 15, so the first (least significant) bit
'is bit 0.
'Note: we do not inspect bit 15, the sign bit.
Function IntegerBitIsSet(theInteger%, bit As Byte) As Boolean
Static i&, b%()
If (Not Not b) = 0 Then
ReDim b(0 To 14)
For i = 0 To 14
b(i) = 2 ^ i
Next
End If
If bit < 15 Then IntegerBitIsSet = theInteger And b(bit)
End Function
'------------------------------------------------------------------
MsgBox IntegerBitIsSet(255, 7) '<--displays: True
MsgBox IntegerBitIsSet(230, 0) '<--displays: False
MsgBox IntegerBitIsSet(16384, 14) '<--displays: True
MsgBox IntegerBitIsSet(-16383, 0) '<--displays: True
Source: academy.excelhero.com
22
vba bits to byte
By Excel Hero
on Feb 03, 2021
Excel Hero
on Feb 03, 2021
'Extremely fast VBA function to convert a binary string to a Byte:
Function BitsToByte(bits$) As Byte
Dim i&
Static b() As Byte
If LenB(bits) > 16 Then Exit Function
If LenB(bits) = 16 Then
b = bits
Else
b = String$(8 - Len(bits), "0") & bits
End If
For i = 0 To 14 Step 2
BitsToByte = 2 * BitsToByte Or (b(i) Xor 48)
Next
End Function
'Example:
MsgBox BitsToByte("00001100") '<--displays: 12
MsgBox BitsToByte("10000001") '<--displays: 129
'
'
'
Source: academy.excelhero.com
31
excel vba set bit in byte
By Excel Hero
on Feb 05, 2021
Excel Hero
on Feb 05, 2021
'Extremely fast VBA function to test if a specified bit is set
'within a Byte.
'Bits are numbered from 0 to 7, so the first (least significant) bit
'is bit 0.
Function ByteBitIsSet(theByte As Byte, bit As Byte) As Boolean
Static i&, b() As Byte
If (Not Not b) = 0 Then
ReDim b(0 To 7)
For i = 0 To 7
b(i) = 2 ^ i
Next
End If
If bit < 8 Then ByteBitIsSet = theByte And b(bit)
End Function
'------------------------------------------------------------------
MsgBox ByteBitIsSet(255, 7) '<--displays: True
MsgBox ByteBitIsSet(230, 0) '<--displays: False
Source: academy.excelhero.com
15
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